AI Tutor
Imagine a tiny frog that can only hop forward 3 spaces at a time. If that frog takes 4 equal hops in a row, where will it land?
We can see the frog's journey clearly using a number line, which is a straight line marked with numbers in order from left to right.
Every multiplication model on a number line starts at 0.
The number of jumps represents the first factor, and the jump size represents the second factor.
Because 4 jumps of 3 spaces land directly on 12, we know that 4×3=124 \times 3 = 12.
What happens if our frog decides to take 3 bigger jumps of 4 spaces instead?

Same Landing, Different Jumps

Whether you make 4 jumps of 3 or 3 jumps of 4, both paths lead to the exact same landing number.
This visual demonstrates that swapping the order of factors gives the same result: 4×3=3×44 \times 3 = 3 \times 4.
How do we draw and solve a brand-new problem like 5×25 \times 2 from scratch?

Step-by-Step with 5 × 2