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Staring at a system of equations where every variable is trapped inside a fraction can look intimidating. But you can eliminate every fraction in one single step without changing the solution.
A coefficient is the number multiplied by a variable, such as the 23\frac{2}{3} in 23x\frac{2}{3}x. A system of simultaneous equations is a set of two or more equations sharing the same variables that must all be true at the same time.
To clear fractions, we find the least common denominator (LCD)β€”the smallest positive integer that each denominator divides into evenlyβ€”and multiply every term on both sides by it.
What happens when both equations in a system contain different fractions? Let's clear them systematically.

Clearing Denominators in a System

Consider the following simultaneous linear system:{12x+23y=414xβˆ’16y=12\begin{cases} \frac{1}{2}x + \frac{2}{3}y = 4 \\[6pt] \frac{1}{4}x - \frac{1}{6}y = \frac{1}{2} \end{cases}
For Equation 1, the denominators are 22 and 33, giving an LCD of 66. For Equation 2, the denominators are 44, 66, and 22, giving an LCD of 1212.
Multiplying Equation 1 by 66 gives 6(12x)+6(23y)=6(4)6\left(\frac{1}{2}x\right) + 6\left(\frac{2}{3}y\right) = 6(4), which simplifies directly to 3x+4y=243x + 4y = 24.
Multiplying Equation 2 by 1212 gives 12(14x)βˆ’12(16y)=12(12)12\left(\frac{1}{4}x\right) - 12\left(\frac{1}{6}y\right) = 12\left(\frac{1}{2}\right), which simplifies to 3xβˆ’2y=63x - 2y = 6.
Now that our equations contain only integers, how do we solve for xx and yy?

Solving and Verifying the System