AI Tutor
Imagine you have 4 prize tickets, but the arcade machine glitches and multiplies your score by 1,000. How do you find your total without adding 1,000 four separate times?
In our number system, moving one place to the left makes a value ten times greater. Because 1,000=10×10×101,000 = 10 \times 10 \times 10, multiplying by 1,000 shifts every digit exactly three places to the left.
What does this slide look like when we multiply a single digit?

The Three-Place Shift

Let's find 6×1,0006 \times 1,000. We start with the digit 6 in the ones place and shift it three columns to the left.
The 6 lands in the thousands column. We fill the empty hundreds, tens, and ones places with placeholders (zeros) to show their new value: 6,0006,000.
Does this exact same rule work if our starting number has two digits?

Multiplying Larger Numbers

To solve 43×1,00043 \times 1,000, every digit in 43 shifts three places to the left together.
The 4 tens move to 4 ten-thousands, the 3 ones move to 3 thousands, and three placeholder zeros hold the empty spaces to give 43,00043,000.