lesson

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Imagine you have 10tospendentirelyon2 drinks and $1 snacks. You could buy 3 drinks and 4 snacks, or 5 drinks and no snacks โ both combinations hit your total exactly.
In algebra, we write this relationship as a linear equation in two variables: 2x+y=10. Unlike single-variable equations with just one answer, equations with two variables have infinitely many paired solutions.
A solution is written as an ordered pair (x,y), where the first number replaces x and the second replaces y to make the statement true.
๐A clean visual breakdown of an ordered pair and substitution. On the left, display '(x, y)' with callout lines pointing 'x = First Value (Input)' and 'y = Second Value (Output)'. In the middle, an arrow leads to the equation '2x + y = 10'. On the right, show the substitution with (3, 4): '2(3) + 4 = 6 + 4 = 10', ending with a bright green checkmark card labeled 'True Statement -> Solution!'. Use a light background (#f8fafc), dark text (#1e293b), soft borders, and vivid blue (#2563eb) and emerald green accents.
How can you tell if a specific mystery pair actually works for an equation?
Testing a Candidate Pair
To check if an ordered pair is a solution, substitute the x-value and y-value into the equation and simplify both sides.
Let's test if (4,1) solves 3xโ2y=10. Replace x with 4 and y with 1: 3(4)โ2(1)=12โ2=10 Since 10=10, the pair (4,1) is a valid solution.
๐Side-by-side comparison cards testing two points for 3x - 2y = 10. Card 1 tests (4, 1): '3(4) - 2(1) = 12 - 2 = 10', shows '10 = 10' with a green checkmark badge 'Valid Solution'. Card 2 tests (2, 3): '3(2) - 2(3) = 6 - 6 = 0', shows '0 != 10' with a red 'X' badge 'Not a Solution'. Responsive card layout with neat math formatting, rounded corners, subtle shadows.
Testing given points is easy, but what if you need to create your own solutions from scratch?
Generating Ordered Pairs
Because every input x links to an output y, you can pick any convenient value for x and solve the remaining single-variable equation for y.
Consider y=2xโ1. If we choose x=0, then y=2(0)โ1=โ1, giving the pair (0,โ1). If we pick x=3, then y=2(3)โ1=5, giving (3,5).