lesson

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A smartphone camera flash needs around 10 watts of power to illuminate a dark room, yet its tiny battery can only safely deliver a fraction of that in a millisecond burst.
To solve this, circuits trickle-charge a capacitor over several seconds, storing electrostatic potential energy and dumping it all in a microsecond flash.
How much energy does that electric field actually hold, and how do we calculate it?
The Energy in an Electric Field
Capacitance (C) measures how much electric charge (Q) a component stores for every volt (V) of electrical potential across it, defined by C=VQ.
When you push the first tiny bit of charge onto an uncharged capacitor, it encounters zero opposing voltage. But as charge builds up, the voltage rises linearly, making each subsequent charge harder to push.
📊Interactive diagram
Because the voltage increases linearly from 0 to V, the average potential during charging is simply 21V. The total stored energy (E) is the work done: E=21QV.
Substituting Q=CV gives the standard design formula: E=21CV2=2CQ2
What happens to the stored energy when you double the operating voltage of a power supply capacitor?
Worked Example: Energy Scaling
Suppose a studio strobe flash uses a 470 μF capacitor charged to 300 V. Let's calculate the total stored energy delivered to the flash tube.
📊Interactive diagram