lesson

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What happens if you feed a number into an assembly line of math operations, and halfway through, a conveyor belt drops it off a cliff? When you chain equations together, valid inputs can suddenly turn into illegal mathematical operations like dividing by zero.
The domain of a function is the set of all real input values x that produce a real output, while the range is the complete set of resulting output values y.
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What makes an input 'illegal' in precalculus? Let's inspect fractions where variables lurk in the basement.
Rational Functions
A rational function is a fraction of two polynomials, written as R(x)=Q(x)P(x)β. Because division by zero is undefined in real numbers, the domain excludes every x-value where the denominator Q(x)=0.
Consider the function f(x)=x2β92x+1β. Setting the denominator x2β9=0 yields (xβ3)(x+3)=0, meaning the domain is all real numbers except x=3 and x=β3, written in interval notation as (ββ,β3)βͺ(β3,3)βͺ(3,β).
To find the range analytically, solve the equation for x in terms of y. If y=xβ52xβ, cross-multiplying gives y(xβ5)=2x, which rearranges to x(yβ2)=5y, or x=yβ25yβ. Since yβ2 cannot be zero, the range excludes 2: (ββ,2)βͺ(2,β).
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A frequent pitfall is simplifying a fraction before checking its domain. For g(x)=xβ2x2β4β, canceling (xβ2) leaves x+2, but x=2 is still excluded from the domain because the original denominator was zero, creating a removable discontinuity (a hole) at (2,4).
What happens when the output of one function becomes the direct input of another? That requires passing through two security checkpoints.
Composite Functions
A composite function, written (fβg)(x)=f(g(x)), applies the inner function g first, and then applies the outer function f to that result.