AI Tutor
If a sequence starts at 77 and jumps by 44 every single step, what is the 500500th number? You definitely don't want to hit "+4+ 4" on your calculator 499499 times.

The Logic of the Jumps

An arithmetic sequence is simply a list of numbers where each term is found by adding a constant value called the common difference (dd) to the previous term.
Let's watch how the terms build from the very first number, which we call a1a_1.
Notice the counting trick: to reach the 2nd term, you take 11 jump. To reach the 4th term, you take 33 jumps.
So to get from term 11 to any term nn, how many jumps of size dd must you take?

Deriving the Formula

Because you start at the first term, you always make exactly nβˆ’1n - 1 jumps to reach position nn.
This gives us the explicit nnth-term formula: an=a1+(nβˆ’1)da_n = a_1 + (n - 1)d
Mathematicians across ancient civilizations, including the 7th-century Indian scholar Brahmagupta, formalized these linear progression rules to calculate astronomical cycles and commerce debts without tedious manual addition.
How does this look with real numbers when the sequence goes down instead of up?